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Simple Geometry : Constructing a Golden Triangle

Given a line segment of length 1 inch, how do I construct a line segment of squareroot(6), squareroot(7), squareroot(8), etc.
Also, given a wire of total length 4236 feet, how do I construct a golden triangle from the wire?

Solution Preview

1. Draw a line segment AB of length 1 inch. Now, extend AB to C such that BC = X inches when squareroot(X) is desired. Now with line AC (of total length X+1 inches) as diameter, draw a semicircle. Draw a vertical line from B to intersect ...

Solution Summary

A "golden triangle" is constructed from a legth of wire. Line segments are investigated.