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Koch Snowflake

Part I: Here we will look at the Koch snowflake which is constructed as follows:

a. Start by drawing an equilateral triangle: we will call this T1 as it is the first step in the process.

b. Next, on each of the three sides of the equilateral triangle, identify the middle third of that side, erase it, and then put an equilateral triangle here (facing outward). Call the new shape T2.

c. Next, on each of the sides of the new shape T2, repeat step b, that is erase the middle third of each side and replace it with a new equilateral triangle facing outward. Call this new shape T3.

d. We can continue the procedure indefinitely, producing shapes T4, T5, . . .. If we were able to repeat this infinitely many times, we would get Tâ?? which is the Koch snowflake.

Part II: Then Let A denote the area of T1 and P the perimeter of T1.

a. Find the area of T2,T3,...

b. What is the area of Tâ???

c. Find the perimeter of T2, T3, . . .

d. What is the perimter of Tâ???

e. In what ways do you see selfâ?"similarity in Tâ???

Solution Summary

The Koch diagram is advised.