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Probability

2.20) Suppose a shock causes a unit damage to the machine with probability 0.1 and no damage with probability of 0.9. Successive shocks are independent. Suppose the damages are cumulative and the machine can withstand at most four units of damage. (That, is the machine fails when the fifth unit of damage is inflicted on it.) What is the probability that the kth shock kills the machine?

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^ denotes power

Probability of damaging shock=p= 0.1
Probability of non damaging shock=q= 0.9

When k shocks have been administered , it includes 5 damaging shocks and (k-5) non damaging shocks . ...

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The solution calculates probability.

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