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Solving First Order Separable Ordinary Differential Equation With Initial Value

Solve the initial value problem
dy/dx=(3x^2+4x+2)/[2(y-1)], y(0)=-1

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Solution : From the equation we have
2(y-1)dy-(3x^2+4x+2)dx=0 , thus 2(y-1)dy=(3x^2+4x+2)dx. It is a ...

Solution Summary

An initial-value problem is solved.

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