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What is the solution of y'' + 2y' + 2y = 0, y(0) = 2, y'(0) = -3?

Find the solution of the initial value problem: y'' + 2y' + 2y = 0, y(0) = 2, y'(0) = -3

Solution Preview

Solution. Its characteristic equation is
r^2+2r+2=0
So, r1=-1+i, r2=-1-i
So, y1=e^(-x)sinx y2=e^(-x)cosx are ...

Solution Summary

A characterisitic equation is found and the initial-value problem is solved.

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