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Vectors in linear algebra

Suppose that a "skew" product of vectors in R2 is defined by (u,v)=u1v1-u2v2

Prove that (u,v)squared >equal too (u,u)(v,v). (NOTE; This is just the reverse of the Cauchy- Schwartz inequality for the ordinary dot product.)

Solution Summary

This is a proof of the reverse of the Cauchy-Schwartz dot product inequality.