Diagonalizable
Not what you're looking for?
Suppose A is diagonalizable with distinct eigenvalues...
See attached file for full problem description.
Purchase this Solution
Solution Summary
This is a proof regarding a diagonalizable matrix and orthogonal projections.
Solution Preview
I will use the notation a1...ak for the eigenvalues (rather than using lambda, which is difficult to write).
I will also denote just by m the minimal polynomial of A. We know that because A is diagonalisable:
m(t)=(t-a1)*...*(t-ak)
So P_j(t)=(t-a1)*...*(t-ak)/c_j where in the product the factor (t-aj) is missing, as it ...
Purchase this Solution
Free BrainMass Quizzes
Know Your Linear Equations
Each question is a choice-summary multiple choice question that will present you with a linear equation and then make 4 statements about that equation. You must determine which of the 4 statements are true (if any) in regards to the equation.
Probability Quiz
Some questions on probability
Geometry - Real Life Application Problems
Understanding of how geometry applies to in real-world contexts
Graphs and Functions
This quiz helps you easily identify a function and test your understanding of ranges, domains , function inverses and transformations.
Solving quadratic inequalities
This quiz test you on how well you are familiar with solving quadratic inequalities.