Surface Area of a Revolving Curve
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Using the formula for the surface area of a revolving curve about the y-axis:
S=∫2πx√(1 + (dx/dy)²)dy throughout a,b
Find the area of the surface generated by revolving the curve about the y axis within the given boundaries
x=√(2y-1) 5/8≤y≤1
the revolving base passes thru the point (1/2, 5/8)
the revolving top passes thru the point (1,1)
Please be detailed, showing the complete derivation, integration and substitution of limits to find the area.
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Solution Summary
This shows how to use a given formula to find surface area of a revolving curve.
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x=√(2y-1)
=>dx/dy=(1/2)[(2y-1)^(-1/2)]*2=1/√(2y-1)
S=∫2πx√(1 + ...
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