Q on Lebesgue integrals.
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In a previous problem I posted here:
Let f(x) be a positive continuous function on [0,1/2], f(x) =< 1/2.
Let A = { (x,y) : 0 =< x = 1/2, 0=<y=< f(x)}
Prove that;
m*(A) = integral from 0 to 1/2 of f(x)dx.
Now knowing that the above is true, I want to show that the integral is lebesgue measurable, that is, the area under the curve is Lebesgue measurable.
In the previous problem it was proven that the inner and outer measures are equal to the integral, but then they are both equal, I wonder if I have to prove any more results? If so, please show me.
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Solution Summary
This solution is comprised of a detailed explanation to show that the integral is lebesgue measurable, that is, the area under the curve is Lebesgue measurable.
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A set is Lebesgue measurable if and only if its inner measure is equal to its outer ...
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