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Integrals : Position of Particle; Derivatives : Maximum Values

1. V(t) = 32t^2-8t, find position of particle on x axis at t = a, when t = 0, x = -6

2. L(d) = 167.5(sin(2 pi/366)(d-80))+738, find the day with the longest daylight.

Solution Summary

The position of a particle and a maximum value is found. The solution is detailed and well presented. The response received a rating of "5/5" from the student who originally posted the question.