2.) Determine all values for which the series Σ (for n=1 to ∞) (2^n(sin^n(x))/n^2 converges.
3.) Find the interval of convergence of the series Σ (for n=1 to ∞) (3^n (x-2)^n)/((the square root of (n+2)) 2^n)
4.) Suppose the interval of convergence of the Maclaurin series for f(x) is -2 < x < 2.
If the Maclaurin series for (the integral from 0 to x) f(t) dt is obtained by integrating
term-by-term, which of the following could be the interval of convergence of new
I. -2 < x < 2 III. -2 ≤ x < 2
II. -2 < x ≤ 2 IV. -2 ≤ x ≤ 2
a.) I only c.) II and III e.) I, II, III, IV
b.) IV only d.) I, II, III
This is a set of questions regarding convergence of series.