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Integral : Average Value of a Function

Find the numbers b such that the average value of f(x) = 2 + 6x - 3x^2 on the interval [0, b] is equal to 3.

I know that fave = (1/b-a) (integral sign, b,a) f(x) dx , but I can't figure out how to isolate the b in that equation to find the unknown b.

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