Please see the attached file for the fully formatted problems.
Evaluate the surface integral SSs x dS, where S is part of the plane x = 2y = 3z = 6 that lies in the first octant.
Surface integral of x.dS over S where S is part of the plane x+2y+3z= 6 which lies in the first octant.
The surface integral can be transformed into a double integral over R (in the the cartesian plane).
x+2y+3z = 6
Write z = F(x,y) = ...
A surface integral is evaluated.