Purchase Solution

Continuous Maps, Homomorphisms and Cyclic Groups

Not what you're looking for?

Ask Custom Question

Let f: S^n --> S^n be a continuous map.
Consider the induced homomorphism f*: H~_n (S^n) --> H~_n (S^n), where
H~_n is a reduced homology group. Then from the fact that H~_n (S^n) is an infinite
cyclic group, it follows that there is a unique integer d such that
f*(u) = du for any u in H~_n (S^n).

How exactly does "there is a unique integer d such that..." follow from
"H~_n (S^n) is an infinite cyclic group"?

Purchase this Solution

Solution Summary

Continuous Maps, Homomorphisms and Cyclic Groups are investigated.

Solution Preview

Call H~_n(S^n) G for short.

Take a generator g of the group G, so G = {1, g, g^2, g^3 ,...., g^{-1}, g^{-2},... ...

Purchase this Solution


Free BrainMass Quizzes
Probability Quiz

Some questions on probability

Graphs and Functions

This quiz helps you easily identify a function and test your understanding of ranges, domains , function inverses and transformations.

Geometry - Real Life Application Problems

Understanding of how geometry applies to in real-world contexts

Know Your Linear Equations

Each question is a choice-summary multiple choice question that will present you with a linear equation and then make 4 statements about that equation. You must determine which of the 4 statements are true (if any) in regards to the equation.

Multiplying Complex Numbers

This is a short quiz to check your understanding of multiplication of complex numbers in rectangular form.