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Regarding how to find vertex and intercepts for quadratic equations

Problem:

Find the vertex and intercepts for y = x^2 + x - 6

Solution Preview

Vertex:

The vertex of the graph of y = a x2 + b x + c is the point where the axis of symmetry meets the parabola itself.
It is either the highest point (the 'top of the hill') if the parabola opens downwards or the lowest point (the 'bottom of the valley') if the parabola opens upwards.
In this case it is ...

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