finding the closest to a point
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Find the point on the graph of the equation y^2 = 4x that is closest to the point (2,1).
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This solution is comprised of a detailed explanation to find the point on the graph of the equation y^2 = 4x.
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the distance of a point on y^2 = 4x to the point (2,1)
s = sqrt{(x-20^2 + (y-1)^2}
Square of the distance
=> f = s^2 = ((y^2/4) - 2)^2 ...
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