Share
Explore BrainMass

Equation for the tangent line to a graph.

Please choose the correct answer and indicate final answer.

11. f(x) = (x + 4)^1/2. An equation for the tangent line to the graph of f(x) at the point where x = 77 would be

x - 6y + 13 = 0
x - 8y + 20 = 0
x - 10y + 29 = 0
x - 12y + 40 = 0
x - 14y + 53 = 0
x - 16y + 68 = 0
none of these

12. If f(x) = (x + 2 ln x)^2 , then f '(x) =

(2/x)(x + 1)(x + ln x)
(2/x)(1 + ln x)
(2/x)(x + 2)(x + 2 ln x)
(2/x)(x + 2 ln x)
(4/x)(1 + 2 ln x)
(4/x)(x + 2)(x + 2 ln x)
none of these

Solution Preview

Please choose the correct answer and indicate final answer.

11. f(x) = (x + 4)^1/2. An equation for the tangent line to the graph of f(x) at the point where x = 77 would be

x - 6y + 13 = 0
x - 8y + 20 = 0
x - 10y + 29 = 0
...

Solution Summary

The equation for the tangent line to a graph is found. The solution is detailed and well presented. The response received a rating of "5/5" from the student who originally posted the question.

$2.19