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Circles

Secants QM and RM intersect the circle at S and T as shown,

a) IF RV=12,VS=4,and TV=8 find VQ.

OK so i figured it follows this theorem : If 2 secant segments are drawn to a circle from the same external point, then the products of the length of each secant and the length of its external segment are equal....

So i mapped it out like this
16(4)=(x=8)8
64=8x =64
x= 8

Corrections? I think I did this wrong though

B) If QM=16, SM=5, and TM=4 find RM...

16(5)=(x=4)4
80=4x +16
64=4x
x=16

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