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Maximum Value on an Interval

Find the absolute maximum value for f(x) = x^2 - 4x - 32 on the interval [-3, 9].

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30
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Solution Preview

We have f(x) = x^2 - 4x - 32
Differentiating, we get f'(x)=2x-4=2(x-2)
In the given interval [-3, 9], f'(x)<0 for all x belonging to [-3, 2) and ...

Solution Summary

The maximum value on an interval is found. The response received a rating of "5/5" from the student who originally posted the question.

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