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Derivatives

Q#1) Find the equation of the tangent line to y = 2 ln x at the point where x = 8.

Q#2) If f(x) = (x + 2 ln x)^2 , then f '(x) =

Q# 3) f(x) =ln[ (2x^3)(e^(4x + 3)], then f ''(x) = Note: (4x+3) whole power of e

Solution Preview

Q#1) Find the equation of the tangent line to y = 2 ln x at the point where x = 8.

To find the slope of the tangent line at x=8, we need to find the derivative of y = 2 ln x at x=8.

Note that
y'=2(lnx)'=2*(1/x)
So,
y'(8)=2*(1/8)=1/4.

So, the equation of the tangent ...

Solution Summary

This shows how to find a tangent line at a point and first and second derivatives of given functions.

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