Please see the attached file for the fully formatted problem.

My problem lies in manipulating the equation to one which the inverse transform can be taken, but would appreciate this example of convolution worked with some more of the blanks filled. I cannot figure out how the equation
gets manipulated into what appears to be .
The main objective here is to find the inverse Laplace transform for h(s) using convolution.

k and t are separate variables, not a single variable kt.

Side Note: Is there a mathematical method for taking the inverse transform or are there just tables from people who did the original Laplace transform?

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The solution is attached below in two files. the files are identical in content, only differ in ...

Solution Summary

A Convolution Applied to an Inverse Transform Problem. The solution is detailed and well presented. The solution received a rating of "5" from the student who posted the question.

... solution shows how to utilize the convolution property of ...Apply the method of Laplace transforms to solve the ... Then, applying the transform to the equation we ...

... html http://mathworld.wolfram.com/Convolution.html http://sosmath.com/diffeq/laplace/ application/application.html. ... When applying a Laplace transform to a ...

... The convolution property: A convolution between two functions is ... Y (s ) = L[ y (t )] 3. Apply the inverse...Applying the Laplace transform to both sides we obtain ...

... b1) (b2 )] = (20) − 2 1 Its inverse is 1 ... We are going to compute now the convolution integral (Duhamel ... the integral is to be applied to all ...

...Applying Laplace's transform on both sides we get: ... We apply the inverse transform to get i(t): ... e −5 s For the term α we will use the convolution theorem: s ...

...Applying this to the equation system (with respect to x ... The transform of multiplication is convolution, thus ... Now we need to find the inverse transforms of ϕ (k ...

...Convolution with a delta function: http://130.191.21.201/multimedia ... So applying the transform to the equation yields ... This is an inverse transform of a product of ...

... We will apply knowledge from many branches of science and ... not yet exist and even theories applied to classes ... in the Laplace domain gives a convolution in the ...

... nf F n = (− iσ ) F (σ) n ( 12) dx 8) Convolution formulae: L ... 0 and 0 for t <0) Now, we need to apply the inverse Fourier transform...