How many bits does 10^100 (ten power one hundred) have if written in base 2?
Please explain to me the steps, don't just give me the answer, thank you very much.
To find the number of bits for 10^100, we only need to find log(2, 10^100), which means the logrithm of 10^100 with base 2. So log(2, 10^100) = ...
Counting and combination problems are solved.