Solution to a Differential equation
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Solve the Initial Value Problem y'' + 4y' + 5y = 35e^(-4x)
given: y(0) = -3, y' (0) = 1
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Solution Summary
This solution explains a method to solve a second order differential equation with given initial value conditions.
Solution Preview
The complementary function associated with the solution of this equation is found by using the auxiliary equation. Please see the attachment for the full description of the solution.
We have y'' + 4y' + 5y = 35e-4x
First we write the auxiliary equation, which is got by just replacing ...
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