Find the inverse Laplace transform of (s^3+s^2+2/s) / [s^2(s^2+3s+2)]
Using this (or otherwise), Find the solution of the equation y"+3y'+2y = 1-t
Find the transform of the following functions:
f(t) = (1+t^2)[u(t-1)-u(t-2)] where u(t) is the unit step function.
f(t) = sin(t) for 0<t<Pi and f(t)=0 for Pi<t<2*Pi
Please see the attached file.
The solution is attached below in two files. the files are ...
The solution shows how (among other things) to utilize partial fractions and inverse transform to solve a non-homogeneous differential equation.