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Inverse of a function

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Let f(x)=3+x^2+tan(pie*x/2), where -1<x<1.
a. find f-1(inverse) of (3)
b. find f(f-1(5))

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f(x)=3+x^2+tan(pie*x/2)
Given -1<x<1
so pi*x/2 lies in the interval (-pi/2, ...

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