*I first found m or area, by rho(Integral 0 to 3)[(-x^(2) +2x +3) - (3-x)]dx and the result was 9rho/2.
Second, I found Mx, by rho (Integral 0 to 3) [(-x^2 +2x +3)+(3-x)/2][(-x^2 +2x +3)-(3-x)]dx and the result was 54rho/5, therefore y coordinate is 12/5.
Third, I found My, by rho (Integral 0 to 3) x[(-x^2 +2x +3)-(3-x)]dx and the result was 27rho/4, therefore x coordinate is 3/2.
Do these answers work out correctly?
I am sure you know the basic steps of computing the centroid, but i am just going to go over them for completeness and in the process check your answers:
Determine the function which is on TOP and which is on BOTTOM. To do that ...
The centroid of a region is found using integrals.