Find the particular solution of the differential equation : y=C(e^(-2x))sinx + C(e^(-2x))cos x y(0)= 1 y'(0)= 0
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Find the particular solution of the general equation below, given the initial conditions.
Please show all details in the solution, simplifying if possible. Thank you.
y=C(e^(-2x))sinx + C(e^(-2x))cos x
y(0)= 1
y'(0)= 0
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Solution Summary
The expert finds the particular solution of the differential equations. The initial condition possibilities are determined.
Solution Preview
We already have the general solution:
y=C1(e^(-2x))sinx+C2(e^(-2x))cosx
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