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differential equation from calculus II

Given the differential equation: (y^4)(e^2x) + y' = 0

NOTE: The differential equation above is attached in a microsoft word document for better legibility. Additionally my work is attached as a jpeg file.

The questions:

a)Find the general solution.

b)Find the particular solution such that y(0) = 1.


Solution Preview

y^4*e^2x +dy/dx = 0
<br>or dy/dx = -y^4*e^2x
<br>or (-1/y^4)dy = e^2x ...