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Differential equation

Find the general solution of the differential equation: y'' - 2y' + y = (e^x)/x

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Taking the homogeneous part as: y''-2y'+y =0
<br>we get the characteristic equation as r^2 - 2r + 1 = 0,
<br>or (r-1)^2 = 0
<br>whose solution is given as: r1=1, r2=1
<br>Here r1 = r2 = ...

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