Find the general solution of the differential equation: y'' - 2y' + y = (e^x)/x
Taking the homogeneous part as: y''-2y'+y =0
<br>we get the characteristic equation as r^2 - 2r + 1 = 0,
<br>or (r-1)^2 = 0
<br>whose solution is given as: r1=1, r2=1
<br>Here r1 = r2 = ...