(3n^5 w)^2 /(n^3 w)^0
9c^7 w^-4 (-d^2)/(15c^3 w^6 (-d)^2)
5m^-3 /6^-1 m^-2
6+ the square root of 2 / 3- the square root of 2
A) 18+ the square root of 2 / 9- the square root of 2
B) 18 + the square root of 2 / 7
D) 20 + 9 times the square root of 2 / 7
18 / 9^3/2
A) 18^3 times the square root of 81
B) 2 times the square root of 9 / 9
(3n^5 w)^2 /(n^3 w)^0 == ??
Note: I have used * to denote multiplication and make the notations clearer.
Anything raised to the power of 0 is ALWAYS equal to 1. Therefore the denominator which is ((n^3)*w)^0 = 1. And any entity divided by 1 remains unchanged. So we are left with only the numerator which is
In order to evaluate a 'product' raised to a power, we must raise each of the 'members' of the 'product' to the same power. So in our case the 'product' is (3*(n^5)*w). So you raise each member to the same power, which is 2.
Thus, (3*(n^5)*w)^2 = ...
This shows how to simplify fractions that involve polynomials and square roots.