Find inverse f(x)= 1/X-1
Convert to an expression involving exponent Loga 4=3
Laws of exponents.
x^3 -6x^2 +8x=0
Find x, y intercepts 2x^2-4x+1
1. find inverse f(x)= 1/x-1
Let y=1/x-1, then y+1=1/x, then x=1/(y+1). So the inverse of f(x) is
2 Convert to an expression involving exponent LOGa 4=3
log_a 4=3, then a^3=4, a^3 means a ...
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