Find the voltage V where V=V1+V2 using graphical addition and analytical methods, given that V1=3sin(theta+20 degrees) and V2=5sin(theta-40degrees).
V1 = 3*sin(theta+20 degrees)
V2 = 5*sin(theta-40degrees)
Let us assume
theta+20 = phi
V1 = 3*sin(phi)
V2 = 5*sin(phi-60 degree)
Hence the phase difference between two volatages is ...
A graphical addition problem is solved. A diagram is included with this fully-worked solution.