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Find Real Roots of an Equation Given Two of the Complex Conjugate Roots

The equation x^4 - 18x^3 + 121x^2 - 368x + 420=0

has complex conjugate roots (4+j2) & (4-j2). By a process of division and solving a quadratic equation, find all the roots and hence write down all the factors of :

x^4 - 18x^3 + 121x^2 - 368x + 420

Please can you show all working out including the division part of this problem as I would like to understand the process behind this problem for future use.

Please see the attached file for the fully formatted problem.


Solution Summary

The real roots for an equation are found given two of the complex conjugate roots. The solution is detailed and well presented. The response received a rating of "5" from the student who originally posted the question.