If a rock is thrown into the air on small planet with a velocity of 25 meters/second, its height in meters after t seconds is given by V = 25t ? 4.9t2. Find the velocity of the rock when t=3
A particle moves along a straight line and its position at time t is given by s(t) = 2t3 ? 27t2 + 108t where s is measured in meters and t in seconds.
Find the velocity of the particle at time t = 0: _______________ meters/second.
The particle stops moving (i.e. is in a rest) twice, once when t=A and again at t = B where A < B.
A is ____________seconds,
and B is _____________ seconds.
What is the position of the particle at time 18? ________________________ meters.
Finally, what is the TOTAL distance the particle travels between time 0 and time 18? ____________________________ meters.
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The solution ...
Velocity, Time, Distance of a Rock After it has been Thrown are investigated. The solution is detailed and well presented.