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Finding the vertices of a hyperbola.

Find the vertices of the hyperbola with the following equation:

(x-3)^2/25 - (y+4)^2/4 =1

EITHER:

A) (8,-4) and (-2,-4)

B) (5,-4) and (1,-4)

C) (3,-2) and (3,-6)

D) (3,1) and (3,-9)

Solution Preview

(x-3)^2/25 - (y+4)^2/4 =1
In general hyperbola equation is
(x-h)^2/a^2 - (y-k)^2/b^2 =1
So a=5 b=2 h=3 k=-4
(h,k) is the center
So, the ...

Solution Summary

The vertices of a hyperbola are found.

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