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A rectangle has an area of 3648 in ^2 and a perimeter of 268 in.

The length (long side) is _______in.

The width (shorter side) is _____in.

Solution Preview

Assume that the length (long side) is x in, and the width is y in. Then we can set up the following

x y=3648
2 x+ 2y =268


xy=3648 ...

Solution Summary

This provides an example of finding dimensions given perimeter and area.