A rectangle has an area of 3648 in ^2 and a perimeter of 268 in.
The length (long side) is _______in.
The width (shorter side) is _____in.
Assume that the length (long side) is x in, and the width is y in. Then we can set up the following
2 x+ 2y =268
This provides an example of finding dimensions given perimeter and area.