Then **the** events **that** **the** first card **chosen** **is** **a** king **and** **the** second card **chosen** **is** **a** heart are dependent events.
Provide an example of experimental **probability** **and** explain why it **is** considered experimental.

338357 **Probability** **that** Graduating **student** will be **a** member of **a** sports team **Probability** **that** Graduating **student** will be **a** member of **a** sports team Suppose M denote **the** selected **graduate** **is** **male** **and** F denotes **the** selected **graduate** **is** female.

Solution:
Thus, if **a** test taker **is** **randomly** selected, **the** **probability** **that** **a** **student** scores 750 or better **is** 0.1056. **Probability** of required university score **is** determined.

**Probability** **that** **a** **randomly** **chosen** worker reported being unemployed **is** **a** college **graduate** **is** computed as follows:
Pj (X=1|Y=0) = Pj (X=1, Y=0) / Pj (Y=0) = 0.005/0.050 = 0.1
**Probability** **that** **a** **randomly** **chosen** worker reported being unemployed **is** **a** non-college

For Neutral Against Totals
Female 38 54 12 104
**Male** 12 36 48 96
Totals 50 90 60 200
Find **the** **probability** **that** **a** **randomly** selected
**a**) person would be **male**
b) person would be for **the** funding
c) person would both female **and** neutral for funding

If we **randomly** select an employee, there **is** **a** 37/100 **probability** **that** **the** employee **is** **a** female who does not exercise at lunch. 37/100=37%
b) 37%
There are no calculations in excel, but **a** tree **is** drawn in **the** attachment.

What **is** **the** **probability** **that** **a** **randomly** **chosen** **male** prefers Clint's Texas Salsa Hot? 12.07%
b. What **is** **the** **probability** **that** **a** **randomly** **chosen** female prefers Goldwater's Rio Verde? 17.82%
c.

So P(X<=66.15)=P(Z<=0.86)=0.8051 by standard normal table
Find **the** **probability** **that** **a** female **student** **randomly** selected from **the** above population will have **a** height equal **to** greater than 63 inches.

Find **the** **probability** **that** **a** **randomly** selected **student** **is** **male**.
**The** **probability**: 1318/3508=0.3757
36. Find **the** **probability** **that** **a** **randomly** selected **student** **is** **a** nursing major given **that** **the** **student** **is** **a** **male**.
**The** **probability**: 121/1318=0.09181
37.

Here given **that** person selected **is** **male**, P(**A**) = 300/500 = 0.6
**And** person selected are **male** **and** having account major = P(**A** **and** B) = 100 /500 = 0.2
Then **the** **probability** of selecting **is** an accounting major, given **that** **the** person selected **is** **a** **male**