29310 Electrical Energy Conversion: Synchronous **Generator** Electrical Energy Conversion: Synchronous **Generator** a. A phasor **diagram** for this **generator**
Where
- Power factor = 0.832 lagging, the corresponding angle phi = 37.4 degrees.

Determine the system fault kVA and the fault currents at the 415 V and 110 V busbars for short **circuit** faults on the transformer input or output terminals. Work in p.u. values of impedances.

Below is the **diagram** of a simple AC **generator** (image courtesy of http://www.ac-motors.us):
There are 4 main parts of a simple AC **generator**: the magnet, the coil made of electric conducting material, the slip rings and the carbon brushes.

113364 Sequence **generator** **circuit** using JKs. Sequence **generator** **circuit** using JKs. Please see attached file.
JK Flip flops switch their state when J=K=1, and in this case when the clock pulse falls from "1" to "0".

30642 Phasor **Diagram** for Synchronous **Generator** Phasor **Diagram** for Synchronous **Generator** Solution:
Given that the **generator** is 24kV and Y-connected, we have the rated voltage per phase U = 24/1.732 = 13.86 kV
Operating phase A to neutral voltage

An RL **circuit** consists of a resistor R = 63 ohms, an inductor, L = 45 mH, and an ac **generator** with an rms voltage of 120 V.
(a) At what frequency will the rms current in this **circuit** be 1.5 A?

frequency, f = Emax/(2Ï€NBA) = 180/(75/280) = 672Hz
Power = (Voltage x Current) = [Voltage x (Voltage/Resistance)]
(Since from Ohm's Law, Voltage = Resistance x Current, so, Current = Voltage / Resistance)
Therefore, P= V2/R
For the given **circuit**

Vs is the output voltage at the **generator** and Vcustomer is the voltage at customer end.
Now, we know that Vcustomer=10 kV and Pcustomer=100k watts. Since p=V*I, therefore, current I in this **circuit** is 100000/10000=10(A).

145861 Explaining the Meaning of a Simple **Circuit** **Diagram** Explaining the Meaning of a Simple **Circuit** **Diagram** The top **diagram** shows a gate (or component) that has three inputs. Two of the inputs are fed by A and the third by B.

A sine wave **generator** of know amplitude and frequency replaces the battery and the RMS current that flows and the power dissipated is deduced.