267635 **Frequency**, **Speed** **of** **Light**, **Wavelength** **in** **a** **Vacuum** **Frequency**, **Speed** **of** **Light**, **Wavelength** **in** **a** **Vacuum** f = v/L, where f = **frequency**, v = velocity **of** **light** **in** **vacuum** and L = wave length
f = 3 * 10^8 m/s / 656.3 * 10^-9 m
f = 4.571 * 10^14 cps

200527 The **wavelength** and phase **speed** **of** microwaves The **wavelength** and phase **speed** **of** microwaves (i) The phase **speed** **of** wave **in** **vacuum** is the velocity **of** **light**.

Find the **speed** **of** **light** **in** (**a**) water, (b) crown glass and (c) diamond
Solution:
Refractive index **of** **a** medium = **Speed** **of** **light** **in** **vacuum**/**Speed** **of** **light** **in** the medium
**Speed** **of** **light** **in** the medium = **Speed** **of** **light** **in** **vacuum**/Refractive index **of**

198945 **Wavelength** and phase **speed** **of** microwaves **Wavelength** and phase **speed** **of** microwaves The answer is given clearly **in** the word file attached below.
(i) The phase **speed** **of** wave **in** **vacuum** is the velocity **of** **light**.

19271 Refraction and **speed** **of** **light** n medium. Refraction and **speed** **of** **light** n medium. Please see the attached file.
The **speed** **of** **a** wave is:
Where is the **wavelength** and f is its **frequency**.

increase the **frequency** **of** the **light**
True
The relation for the **speed** **of** **light** **in** air
Shows that for the **light** **of** higher **frequency** the **wavelength** **of** **light** **in** the medium is less and for less **wavelength** the fringe width will be less.
5

**Speed** **of** **light** **in** **vacuum**/**Speed** **of** **light** **in** the given medium = μ
Hence, **speed** **of** **light** **in** oil = coil = **speed** **of** **light** **in** **vacuum**/1.24 = 3 x 108/1.24 = 2.42 x 108 m/s
**Speed** **of** **light** **in** water = cwater = 3 x 108/1.33 = 2.26 x 108 m/s
As we know,

Solution 23:
The **speed** **of** **light** will be less **in** atmosphere than **in** **vacuum** as **in** atmosphere the **light** interacts with particles which lowers the **speed** down.

**frequency** (f) into **wavelength** by using the relation:
c is the **speed** **of** **light** (2.998x108 m/s)
3. **a** photon **of** X-ray with energy **of** 2.30 x 10-15 J........**in** kg
First, find the **frequency** using the relation:
(E is energy)

For any wave the product **of** **wavelength** and **frequency** is the **speed** **of** the wave; **in** this case that **speed** is the **speed** **of** **light**.