= 120 V and I = RMS current I = P/Vcosφ = 375/(120 x 0.72) = 4.34 A iv) Real power is also given by: P = I2R' where R' is the total resistance in the circuit 375 = 4.342R' R' = 19.91 ohm In the circuit R = 10 ohm, hence 9.91
See Eq 3 Both the current and power in the circuit varies with the angular frequency w. As w appears in the impedance, for maximum current amplitude and average power the impedance of the circuit must be a minimum.
116621 Lightbulbs in a series/parallel Lightbulbs in a series/parallel (see attachment for complete solution and diagram) a) Three bulbs in series : Power dissipated in a resistance is given by the following expression : P = VI = I^2R = V^2
d2) R1 = 100 Ω, R2 = 300 Ω, R3 = 200 Ω In the circuit diagram below, the total current flowing through the circuit is 1 Amp, calculate the total power using P = I2*R total, and then verify the answer by calculating power dissipated in each of the resistors
In order to get power factor 1, . The power factor can be increased to be 1 by connecting a capacitance parallel to the old as shown in figure. Now, RCL series circuit are analyzed.
P = V2/R = 120*120/(9.70*103) = 1.48 W 7. In the circuit shown in the figure , the voltage across the 2.00 resistor is 12.5 . What is the emf of the battery?
If a light bulb has half the resistance of a 100-W lightbulb, what would be its wattage? Assume both bulbs are attached to the same 120-V circuit.
leaving the appliance on for this time 5 Days is time T = 5 x 24 = 120 h Power is 1800 W so in 1 hour the dryer uses E = 1800 x 1 = 1.8 KWh In 5 days it would use E(5) = 1.8 x 120 = 216 KWh As 1 KWh costs 9.4 c 216 KWh will cost 216
We know that power dissipated in a resistor is give by P = I x V , where I and V are current and voltage on the resistor respectively. But this is for constant I and V.
348312 Current flowing in the series circuit, Power dissipated, DC current through the handset Current flowing in the series circuit, Power dissipated, DC current through the handset Please see the attachment as well for clear symbols and drawing in (