I'm in dire need of help with coding this function/small program. I have 2 codes that I am working with just need one tha works well. Any help that can be provided would be appreciated greatly. How it should work: Write a function that accepts a pointer to a string as an argument and returns the number of words contained in the string. Must actual count the number of words. User must be able to input a stringand then pass the string to the function. The function must also display the average number of letters in each word. Codes that I am working with below: 1.) ---------------------------------------------------------------------------------------------------------------- #include "stdafx.h" #include #include #include #include using namespace std; int main () { const int size = 5; char WordString[size]; string sentence; int wordlength = 5; int wordcount = 0; int i = 0; cout<<"Enter a string or sentence: "; cin.getline( WordString, size ); while( i <= sentence.length() ) { if( isalpha( sentence[i] )) { wordlength++; } else if ( wordlength > 0 ) { wordcount++; wordlength = 5; } i++; } cout<<"There are " << wordcount << "words in this sentence."<< endl; cin.get(); return 0; } _______________________________________________________________________ 2.) Tried working with this one also but program doen't allow me to do anything. Exits to early ----------------------------------------------------------------------------------------------------- #include "stdafx.h" #include #include #include #include using namespace std; int main() { char abcd[100]; //string int wordcnt=0; //word counter! fflush(stdin); cout << "\nEnter string: "; cin.getline(abcd,wordcnt); if(abcd[0]!=' ') wordcnt++; //account for the first word for(int i=0; abcd[i]!='\0'; i++) { if(abcd[i]==' ') { //increment i until non-space char is found while(abcd[i]==' ') i++; //account for spaces at end and increment wordcnt if(i <= strlen(abcd))wordcnt++; } } cout << "\n\nWord Count: " << wordcnt; cin.get(); return 0; }