Beginning Differential Equation & Pedantic Diff Calculus Questions (2 total) ===================================================================== To whom it may concern: First and foremost, greetings from Brooklyn, NY, USA! Although I'm a part-time adult college student, my question does not related to any class I am currently taking. I'm merely trying to sharpen an improve my rusty (and never particularly sharp) math skills. Just for fun, I began reading my "new" book, "Differential Equations" by E. J. Maurus, published in 1917 (perhaps "new" was the wrong word ;-). I've run into two questions already (and I'm only on page two!); perhaps you can take a shot at them? N.B. Monospace font required. Question 1: ----------- Quoting from the book: ----------------------------------------------------------------- Example 2. Form a differential equation by eliminating the constants c1 and c2 from the equation x 2x y = c1*e + c2*e Since there are two constants to eliminate, three equations are needed. The two extra equations are formed by differentiating the given equation twice, giving 2 dy x 2x d y x 2x -- = c1*e + 2*c2*e and --- = c1*e + 4*c2*e dx 2 dx Eliminating, by determinants or otherwise, we have 2 d y dy --- - 3 -- + 2y = 0 2 dx dx ----------------------------------------------------------------- Quotation ends. I am perfectly comfortable (okay, at least reasonably comfortable ;-) with differential equation related parts of the problem; it's the "Eliminating, by determinants or otherwise" part that stymies me. How would I employ determinants (with which I have some familiarity) to obtain the above answer, and what are some of the other methods I could have used? (I never managed to obtain the final result, although I believe I did verify it.) Question 2: ----------- In addition to having an interest, but no particular facility, in math, I am similarly predisposed towards (English) syntax (grammar). Perhaps this explains why my curiosity was piqued by the following question: [In the interest of brevity, I shall edit more heavily this time.] Quoting from the book: ----------------------------------------------------------------- Example 1. Form a differential equation by eliminating the constant c from the equation x*y = c*sin(x). ... ...differentiating the given equation: x dy + y dx = c * cos(x) dx Eliminating the c, we have the differential equation dy x -- + y = x*y*cot(x) dx ----------------------------------------------------------------- Quotation ends. Once again, it is not the Diff Equation solving that I have a question with. It is the odd (to me) syntax of: x dy + y dx = c * cos(x) dx Of course I threw away my scrap paper, but I think I (eventually) solved the problem as follows: x*y x*y = c*sin(x) --> c = ----- sin(x) Dx[x*y = c*sin(x)] Dx[x*y] = Dx[c*sin(x)] (by chain rule) +- -+ | d(x) d(y) | | ---- * y + x * ---- | = c * cos(x) | dx dx | +- -+ +- -+ | d(y) | | y + x * ---- | = c * cos(x) | dx | +- -+ +- -+ | d(y) | x*y | y + x * ---- | = ------ * cos(x) | dx | sin(x) +- -+ +- -+ | d(y) | cos(x) | x * ---- + y | = ------ * x*y | dx | sin(x) +- -+ d(y) x * ---- + y = cot(x) * x*y dx QED You'll observe that at no time did I write something like: "x dy + y dx = c * cos(x) dx" (Or did I?) Mr. Maurus was not a man to mince words; his entire "Differential Equations" book is less than 7in x 5in and numbers only about fifty pages. If he wrote "x dy + y dx = c * cos(x) dx", then I'm sure he knew what he was doing. Can you explain his terminology, or point me to a math book, web page, etc. that does? Thanks in advance for your help! Cordially, Richard Kanarek RKanarek@Spamcop.net