An RL circuit with switches is shown in the figure. Switch s1 remains closed and s2 remains open for a long time (steady-state). At t=0 switch s1 opens and s2 closes. Find V_1(t) for t > 0.
Answer is B. Because
During steady state, S2 is open, means; the last inductor is cut off from the circuit. So, what we have is, 6 Ohm, 4 ohm and 1 H. And since, it's the DC current which is flowing, inductor acts a short circuit at steady state. ...
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