A half-wave rectifier employing a 12-V-rms 60-Hz sine-wave source and no dc load is filtered using a polarized electrolytic capacitor having a small leakage current. For diodes assumed to have a 0.7V drop independent of current, calculate the resulting output. What is the PIV required of the diode? Show how you arrived at the answer.
Vpeak = Vrms * sqrt(2) = 16.971 V
Subtract the diode drop of 0.7 V
Output peak = 16.971 - 0.7 = 16.271 ...
Vpeak = Vrms * sqrt(2)