Determine the period of the vibration of the system attached.
Mass of the rod M = 3.0 kg
mass of the block m = 0.5 kg
length of the rod l = 1.25 kg
center of gravity of the rod from the end B (lg) = l/2 = 0.625 m
In equilibrium, let the rod makes an angle Qo with the horizontal,
moment about the end B = 0
=> k*(Qo*0.75)*0.75 = M*g*0.625 + m*g*1.25 ......(1)
Let when the end A is pulled down by a distance delta_0 (Do), the rod makes an ...
The solution lays out its working clearly in order to guide the reader through the steps to finding the period of vibration for the system described in the question.