What would be the steps to solve the following two problems?
What volume of 12.0 M HCl is required to make 75.0 mL of 3.50 M HCl?
What is the final concentration of a solution prepared by diluting 35.0 Ml of 12.0 M HCl to a final volume of 1.20 L?
No. of mole = Molarity(mole/l) x Vol(l)
Molarity of the stock solution = 12.0 mol/l = M1
Volume of stock solution = V1
Molarity of ...
The solution explains how to solve two problems of stoichiometry in dilutions and concentrations.