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Volume and final concentration

What would be the steps to solve the following two problems?

What volume of 12.0 M HCl is required to make 75.0 mL of 3.50 M HCl?

AND

What is the final concentration of a solution prepared by diluting 35.0 Ml of 12.0 M HCl to a final volume of 1.20 L?

Solution Preview

No. of mole = Molarity(mole/l) x Vol(l)
Molarity of the stock solution = 12.0 mol/l = M1
Volume of stock solution = V1
Molarity of ...

Solution Summary

The solution explains how to solve two problems of stoichiometry in dilutions and concentrations.

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