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Using Stoichiometry to Solve for Moles

Reaction: CO(g) + 2H2(g) -> CH3OH(g)

1) How many moles of each reactant are needed to produce 3.60 X 10^2g of CH3OH?
2) What are the number of grams of each reactant needed to produce 4.00 moles of CH3OH?
3) How many grams of hydrogen are necessary to react with 2.85 moles of CO?

Solution Preview

Atomic weights: C = 12, H = 1, O =16
Molecular weights: CO = 28, H2 = 2, CH3OH = 32

1. 3.60 X 10^2g of CH3OH = 360 g of CH3OH
= 360/32 = 11.25 moles of CH3OH
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Solution Summary

The accompanying solution provides a detailed explanation of how to solve each question which pertains to the given reaction for this problem. Reasoning is provided to illustrate how each answer was obtained. This solution will serve as a good learning tool to assist a student in answering future questions of this same nature.