An aqueous solution is prepared by diluting 3.30 mL acetone, CH3COCH3, (d=0.789 g/ml) with water to a final volume of 75.0 mL. The density of the solution is 0.993 g/mL. What are the molarity and molality of acetone in this solution? (Use correct significant figures.)
The mass of acetone is
m = 3.30 * 0.789 = 2.6037 grams.
The molecular mass of acetone is 12 * 3 + 1 * 6 + 16 = 58.0 g/mol.
so the moles of 2.60grams of acetone is
n = m / 58 = 2.6037 / ...
It finds the molarity and molality of acetone solution. The solution is detailed and was rated '5/5' by the student who originally posted the question.