Purchase Solution

Reaction of HCl with Ca(OH)2

Not what you're looking for?

Ask Custom Question

What volume, in ml, of 0.750 M HCl would be required to neutralize a 1.50 sample of Ca(OH)2?

Purchase this Solution
Solution Summary

The solution provides a detailed and step-by-step explanation for the problem.

Solution Preview

The reaction is:
2HCl + Ca(OH)2 = CaCl2 + 2H2O

So 2 moles of HCl will ...

Purchase this Solution
Free BrainMass Quizzes
Match Elements with their Symbols

Elements are provided: choose the matching one- or two-letter symbol for each element.

Thermochemistry

The quiz helps in revising basic concepts about thermochemistry.

Organic Chemistry Naming: Alkanes

This is a quiz which is designed to assist students with learning the nomenclature used to identify organic compounds. This quiz focuses on the organic compounds called Alkanes.

Periodic table

General Chemistry - Classification of Matter

This test will assess your knowledge on the classification of matter which includes elements, compounds and mixtures.

View More Free Quizzes
Related BrainMass Solutions

  • Formation of molecules in a reaction

    Our reaction is, HCl + Ca(OH)2 --> CaCl2 + H2O Now, we have to balance the reaction. 2HCl + Ca(OH)2 --> CaCl2 + 2H2O That is to produce one mole of calcium chloride, we need two moles of HCL and one mole of calcium hyroxide.

  • Five involved pH and pOH problems

    (.050L)(.50mol/L) = .025moles of HCl (.075L)(.30mol/L) = .0225moles of Ca(OH)2 BUT you need two HCl to react with every Ca(OH)2, so you'd need .045moles of acid to react with all of the base, and you don't have it, so the acid is limiting- it runs

  • Balancing Example Chemistry Equations

    The g.f.w. of Ca(OH)2 is___ (Ca=40 O=16 H=1) In the reaction Zn0 + Cu+2<--___> Zn+2 + Cu0 the oxidizing agent is the_______. A reducing agent _____ electrons. Complete the following equation.

  • Neutralization

    moles of HCl = moles Ca(OH)2 Molarity HCl times Volume HCl = moles of HCl Grams Ca(OH)2 divided by molecular weight Ca(OH)2 = moles Ca(OH)2 M.W.

  • Ionization and reactions of acids and bases

    (CH3)2NH (aq) + H2O (l) -->/<-- (CH3)2NH2+ (aq) + OH- (aq) D. 2 HNO3 (l) + CaCO3 (s) --> Ca(NO3)2 (s) + H2O (l) + CO2 (g) E. HCl (aq) + KOH (aq) --> H2O (l) + KCl (aq) This solution looks at the ionization and reactions of acids and bases.

  • Acid - Base Reactions

    SOLUTION: Solving for the molarity of Ca(OH)2 solution: M = (1.50 g / 74g /mol) / 0.8 L M = 0.025 mol/L Ca(OH)2 dissociates according to the equation: Ca(OH)2 → Ca+2 + 2OH- 0.025 M 0.025 M 2(0.025 M) = 0.05 M Solving for the [H+]: Kw =

  • Chemistry: Mass of Calcium Hydroxide, Molarity of Sodium Urate

    (OH)2 / 2 moles HCl) Mole Ca(OH)2 = 0.09375 Converting to gram: Mass of Ca(OH)2 = 0.09375 mole Ca(OH)2 (74 g / mole Ca(OH)2) Mass of Ca(OH)2 = 6.9375 g 2.

  • Decomposition and Synthesis Reactions

    2H2O yields 2 H2 + O2 H2 + Cl2 yields 2 HCl 2Li + CaO yields Li2O + Ca CH4 + 2 O2 yields CO2 + 2 H2O H2 + Cl2 = 2 HCl Question 6 (Multiple Choice) Which of the following is a product formed when K reacts with Cl2?

  • Finding the Heat of Reaction (Enthalpy) from Heats of Formation

    Thus, Heat of Reaction = Sum of products-Sum of reactants assume H is heat of reaction for each species Heat of Reaction=[2*H(Ca(OH)2)+2*H(Mg(OH)2)]-[2*H(CaO)+2*H(MgO)+4*H(H2O)] =[2*(-986.1)+2*(-924.7)]-[2*(-635.1)+2*(-601.7

View More Related Solutions