An impure 0.500 gram sample of FeSO4 reacts with 20.0 ml of 0.0200 M KMnO4
Assuming that the impurities do not react with KMnO4 what is the percentage of FeSO4?
The equation given is MnO4- +8H +5Fe+2 -------->Mn2 +5F3+ + 4H2O
so far I got:
.0200l *.0200M MnO4- =4*10-4 Moles of MnO4
How do I get to the moles of Fe?
According to stoichiometry, the moles of Fe will be 5 times the ...
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